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9i^2+34i+21=0
a = 9; b = 34; c = +21;
Δ = b2-4ac
Δ = 342-4·9·21
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-20}{2*9}=\frac{-54}{18} =-3 $$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+20}{2*9}=\frac{-14}{18} =-7/9 $
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